**Moderators:** playgirl, JUS, rodbox

There must be at least two more coin tosses for anyone to reach 10 but at most four (ie when the score reaches 9-9 after three tosses).

H will win in the following circumstances.

(a) If the first two coin tosses are H, H (which is a 25% chance), or

(b) If the first two coin tosses are H, T in some order (50% chance) and then H wins the third toss (50% chance), ie 0.5*0.5 = 25% chance overall, or

(c) If the first two coin tosses are H, T in some order and then T wins the third toss (25% chance overall as in (b)) and then H wins the fourth toss (50% chance), ie 0.25*0.5=12.5% chance overall, or

(d) If the first two coin tosses are T, T (25% chance) and then H wins the next two tosses (25% chance), ie 0.25*0.25 = 6.25% chance overall.

So H would win (25% + 25% + 12.5% + 6.25%) = 68.75% of the time and hence the pot should be split accordingly.

a) HHHH HHHT HHTH HHTT - Heads wins every time

b) HTHT HTHH THHT THHH - Heads wins every time

c) HTTH THTH HTTT THTT - Heads wins 2 out of 4

d) TTHH TTHT TTTH TTTT - Heads wins 1 out of 4

so overall the probability is that Heads would win 11 times in every 16 and should get Ã‚Â£687.50.

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