There are ten (5!/(2!*3!))possible combinations for the last two boxes. Of the ten, three include neither the £100k nor the £250k boxes, one includes both those boxes and six include just one of the £100k and the £250k boxes.
So the chances of having one or both of the £100k and £250k boxes in the last two are 70%.
Moderators: playgirl, JUS, rodbox
Pulse is correct - there are 10 combinations and you can have the £250K box with any one of the other 4 boxes and then the £100K with any of the other 4 boxes less the combination of £100K and £250K which you've already counted - so that's 7/10 or 70%.
On a general point, Pulse's formula is correct - if you choose m objects from a total number of n objects then the number of different ways you can choose them is [n!/m!(n-m)!].
So if I'd asked the same question but the player had both big value boxes at the 8 box stage then the number of ways of choosing 2 boxes from 8 is [8!/2!6!] which is 28 and there are 13 possible combinations containing one or both boxes so the probability would be 13/28.
On a general point, Pulse's formula is correct - if you choose m objects from a total number of n objects then the number of different ways you can choose them is [n!/m!(n-m)!].
So if I'd asked the same question but the player had both big value boxes at the 8 box stage then the number of ways of choosing 2 boxes from 8 is [8!/2!6!] which is 28 and there are 13 possible combinations containing one or both boxes so the probability would be 13/28.
This may have been posted before so apologies if it has but I like it!
The day before yesterday I was 7 years old. Next year I will be 10 years old.
What is the date today & when is my birthday?
The day before yesterday I was 7 years old. Next year I will be 10 years old.
What is the date today & when is my birthday?
Rodney Marsh: "So how's your wife…and my kids?"
Ian Botham: "The wife's fine, but the kids are retarded."
Ian Botham: "The wife's fine, but the kids are retarded."
Let's assume that today is 1-1-10
the day before yesterday, your birthday on 30-12-2009, you were 7
Yesterday, your birthday on the 31-12-2009 you became 8.
Today, on the 1-1-2010 you are still 8.
So this year on the 31-12-2010 you become 9.
So next year on the 31-12-2011 you will be 10
It took me a long time to work it out - I hope I'm right :oops:
In geometry, what word describes two or more circles which have the same centre?
the day before yesterday, your birthday on 30-12-2009, you were 7
Yesterday, your birthday on the 31-12-2009 you became 8.
Today, on the 1-1-2010 you are still 8.
So this year on the 31-12-2010 you become 9.
So next year on the 31-12-2011 you will be 10
It took me a long time to work it out - I hope I'm right :oops:
In geometry, what word describes two or more circles which have the same centre?
QM